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Thursday, January 28, 2010
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Tuesday, January 19, 2010
Dev C++
Microsoft Visual Studio
SQL Server 2008 Nasm Assembler
Oracle Database Express Edition
Math Type
Internet Download Manager
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NOD32 Anti virus
Web Development
Simple (Clint Side)
Yahoo! Site Builder 2.4
Coffee Form Builder
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CSS Spy 1.0
Amaya XML/CSS Editor
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Microsoft Front Page 2003 part 1 2
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Graphic Designing
Adobe Photo shop CS3 10 (Portable)
Corel DRAW X4 (Portable)
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Others(Reader, Lite Code, .NEt, Smart Draw)
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Microsoft .Net Framework
Java SE Runtime Environment 6 Virtual Box
Top 100 CSS Website Templates 95 Website Ready Templates
Java Sample Codes Best Flash Website Templates
Foxit PDF Reader On track Easy Data Recovery
Smart Draw (to Draw Flow charts) K - Lite Code Pack
FlashGet Coming More
Sunday, January 17, 2010
MGT613 - Production / Operations Management Assignment # 2 Solution
MGT613 - Production / Operations Management
Assignment # 2
b. Find out sample proportion defective (p) i.e. no. of defectives per week / Sample size
Sample number | No. Of Defectives | (b)Sample Proportion defective (p) |
1 | 16 | 0.005333333 |
2 | 13 | 0.004333333 |
3 | 20 | 0.006666667 |
4 | 3 | 0.001 |
5 | 18 | 0.006 |
6 | 6 | 0.002 |
7 | 26 | 0.008666667 |
8 | 9 | 0.003 |
9 | 8 | 0.002666667 |
10 | 24 | 0.008 |
11 | 14 | 0.004666667 |
12 | 5 | 0.001666667 |
13 | 12 | 0.004 |
14 | 19 | 0.006333333 |
15 | 18 | 0.006 |
| 211 | 0.070333333 |
a. Find out average population proportion defective which would be the central line on
P-chart (p) i.e. total defectives/ sample size*weeks
p = 211 / (300 * 15)
= 211 / 45000
p = 0.004688889
p = 0.00469 (Approximate)
c. Calculate standard deviation of distribution of proportion defective (σp) using the formula
σp = √ p (1– p)/n. Where n= sample size.
= √ 0.00469 (1 – 0.00469) / 3000
= √ .000001556
= .001247397
σp = .00125
d. Find out upper control limit (UCL) and lower control limit (LCL) using the formula
(UCL p = p + zσ p and LCL p = = p - zσ p )
Use three sigma control limits (z=3)
1) UCL p = p + zσ p
= .00469 + 3 (0.00125)
UCL p = .00844
2) LCL p = p - zσ p
= . 00469 - 3 (0.00125)
LCL p = .00094
e. On the basis of above data construct a p-chart taking sample numbers on x-axis and sample proportion defective (p) on y-axis.
f. Which sample number is showing the highest proportion of defective? Is the process still in control? Analyze the trend in chart.
In the above diagram the sample no.7 is the highest value and this value is out of the upper and the lower limit
UCL p = .00844 and LCL p = .00094
High proportion of the defect is Value = .0087
That’s why we can say that the process is not through the statistical process.
Note...plzz dont copy past material:
Regards
Muhammad azeem
vuguide.tk
MGT613 - Production / Operations Management Assignment # 2
1 16
2 13
3 20
4 3
5 18
6 6
7 26
8 9
9 8
10 24
11 14
12 5
13 12
14 19
15 18
a. Find out average population proportion defective which would be the central line on p-chart (p) i.e. total defectives/ sample size*weeks
b. Find out sample proportion defective (p )i.e. no. of defectives per week / Sample size
c. Calculate standard deviation of distribution of proportion defective (σp) using the formulaσppp=−()/1 n. Where n= sample size.
d. Find out upper control limit (UCL) and lower control limit (LCL) using the formula (UCLpzLCLpzppp=+ p =−σσ and ). Use three sigma control limits(z=3)
e. On the basis of above data construct a p-chart taking sample numbers on x-axis and sample proportion defective (p) on y-axis.
f. Which sample number is showing the highest proportion of defective? Is the process still in control? Analyze the trend in chart.
Tuesday, January 5, 2010
MGT502 - Organizational Behaviour 2nd MDB Solution
· Mr. Iftakhar is an Executive Director at ABC Company. When he first took over as Executive Director, he fired 13 employees who were doing absolutely nothing. This decisive action showed the remaining employees that Mr. Iftakhar was serious about his performance expectations and he would not hesitate to use his powers.
Scenario 02
· Mr. Khalid is a CEO at XYZ Company. Managers and employees respond to Mr. Khalid’s admirable qualities of industriousness, humility and deep personal commitment to his clients. Business leaders in his community also respect his abilities and they feel motivated to donate their time and their corporate funds, because they believe in him.
ANSWER<,,,,,,,,,,,,,,,,,
1:
COERCIVE POWER
2:
CHARISMATIC POWER
Sunday, January 3, 2010
How to use torrent software?
Step 1.