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Thursday, January 28, 2010

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Tuesday, January 19, 2010

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Sunday, January 17, 2010

MGT613 - Production / Operations Management Assignment # 2 Solution

MGT613 - Production / Operations Management

Assignment # 2


b. Find out sample proportion defective (p) i.e. no. of defectives per week / Sample size

Sample number

No. Of Defectives

(b)Sample Proportion defective (p)

1

16

0.005333333

2

13

0.004333333

3

20

0.006666667

4

3

0.001

5

18

0.006

6

6

0.002

7

26

0.008666667

8

9

0.003

9

8

0.002666667

10

24

0.008

11

14

0.004666667

12

5

0.001666667

13

12

0.004

14

19

0.006333333

15

18

0.006

211

0.070333333

a. Find out average population proportion defective which would be the central line on

P-chart (p) i.e. total defectives/ sample size*weeks

p = 211 / (300 * 15)

= 211 / 45000

p = 0.004688889

p = 0.00469 (Approximate)

c. Calculate standard deviation of distribution of proportion defective (σp) using the formula

σp = √ p (1– p)/n. Where n= sample size.

= √ 0.00469 (1 – 0.00469) / 3000

= √ .000001556

= .001247397

σp = .00125

d. Find out upper control limit (UCL) and lower control limit (LCL) using the formula

(UCL p = p + zσ p and LCL p = = p - zσ p )

Use three sigma control limits (z=3)

1) UCL p = p + zσ p

= .00469 + 3 (0.00125)

UCL p = .00844

2) LCL p = p - zσ p

= . 00469 - 3 (0.00125)

LCL p = .00094

e. On the basis of above data construct a p-chart taking sample numbers on x-axis and sample proportion defective (p) on y-axis.




f. Which sample number is showing the highest proportion of defective? Is the process still in control? Analyze the trend in chart.

In the above diagram the sample no.7 is the highest value and this value is out of the upper and the lower limit

UCL p = .00844 and LCL p = .00094

High proportion of the defect is Value = .0087

That’s why we can say that the process is not through the statistical process.



Note...plzz dont copy past material:


Regards

Muhammad azeem

vuguide.tk


MGT613 - Production / Operations Management Assignment # 2 Solution

MGT613 - Production / Operations Management Assignment # 2

A Post Office has initiated Total Quality Management practices to measure the quality of service and detecting whether the process is in control or not through statistical process control methods (SPC). The operations manager collected a random sample size of 3000 postal deliveries and the number of defectives (wrong deliveries) was recorded. The data of 15 weeks are shown as under.
Sample number No. of defectives Sample proportion defective (p)
1 16
2 13
3 20
4 3
5 18
6 6
7 26
8 9
9 8
10 24
11 14
12 5
13 12
14 19
15 18
a. Find out average population proportion defective which would be the central line on p-chart (p) i.e. total defectives/ sample size*weeks
b. Find out sample proportion defective (p )i.e. no. of defectives per week / Sample size
c. Calculate standard deviation of distribution of proportion defective (σp) using the formulaσppp=−()/1 n. Where n= sample size.
d. Find out upper control limit (UCL) and lower control limit (LCL) using the formula (UCLpzLCLpzppp=+ p =−σσ and ). Use three sigma control limits(z=3)
e. On the basis of above data construct a p-chart taking sample numbers on x-axis and sample proportion defective (p) on y-axis.
f. Which sample number is showing the highest proportion of defective? Is the process still in control? Analyze the trend in chart.

Tuesday, January 5, 2010

MGT502 - Organizational Behaviour 2nd MDB Solution

Scenario 01
· Mr. Iftakhar is an Executive Director at ABC Company. When he first took over as Executive Director, he fired 13 employees who were doing absolutely nothing. This decisive action showed the remaining employees that Mr. Iftakhar was serious about his performance expectations and he would not hesitate to use his powers.
Scenario 02
· Mr. Khalid is a CEO at XYZ Company. Managers and employees respond to Mr. Khalid’s admirable qualities of industriousness, humility and deep personal commitment to his clients. Business leaders in his community also respect his abilities and they feel motivated to donate their time and their corporate funds, because they believe in him.


ANSWER<,,,,,,,,,,,,,,,,,

1:
COERCIVE POWER
2:
CHARISMATIC POWER

Sunday, January 3, 2010

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